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Question: A(n) 0.157 kg baseball is thrown with a speed of 28.2 m/s. It is hit straight back at the pitcher with a final speed of 15.2 m/s. What is the magnitude of the impulse delivered to the ball?

The impulse delivered to the ball can be calculated using the formula: Impulse = Change in momentum Since momentum is mass times velocity, then change in momentum is mass times the change in velocity. Change in velocity can be calculated as final velocity minus initial velocity. In this case, the final velocity is negative as the direction has been reversed. Therefore, impulse = mass * (final velocity - initial velocity) Substituting the given values, Impulse = 0.157 kg * ((-15.2 m/s) - (28.2 m/s)) Impulse = 0.157 kg * -43.4 m/s The minus sign indicates that the direction of the velocity has changed. Impulse = -6.81 kg*m/s We are asked for the magnitude of the impulse which always comes out to be positive. Hence, the magnitude of the impulse delivered to the ball is 6.81 kg*m/s.

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