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# Object's Velocity = 15 m/s + 22 m/s = 37 m/s

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Question: 3.0 N • s 11 N • s 25 N • s 56 N • s An object with a mass of 1.5 kg changes its velocity from +15 m/s to +22 m/s during a time interval of 3.5 seconds. What impulse was delivered to the object based on the answer choices above? prove your answer

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. The impulse delivered to the object is 56 N•s. This can be determined from the impulse-momentum theorem, which states that impulse (I) is equal to the change in momentum (Δp). Therefore, this can be expressed as I = Δp = m (v2 - v1) Substituting the given values, we get: I = (1.5)(22 - 15) = 56 N•s

Jan. 6, 2023, 9:11 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user davion's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.

Published: Friday, January 6, 2023

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