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Question: A 2.5 Kg watermelon is dropped off an 8-meter balcony. What will the watermelon’s velocity be right before it hits the ground?
Asked by thevttv56
To calculate the velocity of the watermelon just before it hits the ground, you need to use the formula for the final velocity of an object in free fall: v = sqrt(2*g*h), where: - v is the final velocity; - g is the acceleration due to gravity (9.81 m/s² on Earth); - h is the height. So, in our case: v = sqrt(2*9.81*8), v = sqrt(157.44), v = 12.55 m/s. The watermelon will hit the ground at approximately 12.55 meters per second. It's important to consider that this calculation assumes no air resistance or any other forces acting on the watermelon other than gravity.
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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user thevttv56's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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