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Question: A 10-kg rock falls from a height of 8.0 m above the ground. What is the kinetic energy of the rock just before it hits the ground?
Asked by BIgboy283
The kinetic energy of a falling object can be calculated using the formula for gravitational potential energy that has been entirely converted into kinetic energy as the object falls. The formula is PE = m*g*h, where m is the mass of the object, g is the acceleration due to gravity, and h is the height from which the object falls. Assuming standard gravity (g = 9.8 m/s²), we can substitute the given values into the formula: PE = 10 kg * 9.8 m/s² * 8 m = 784 Joules So, the kinetic energy of the rock just before it hits the ground is 784 Joules.
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