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Illustration of a massive planet with a radius of 2.8 x 10^7 meters symbolizing the concept of gravity and mass.

Ask AI: What is the acceleration due to gravity on a 9.8 X 1026 Kg planet that has a radius of 2.8 X 107 m

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Question: What is the acceleration due to gravity on a 9.8 X 1026 Kg planet that has a radius of 2.8 X 107 m

Asked by thevttv56

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The acceleration due to gravity can be found using the formula: g = G*M/r^2 where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the planet, and r is the radius of the planet. The gravitational constant G is approximately equal to 6.67 x 10^-11 N(m/kg)^2. Let’s substitute the given values into the equation: g = (6.67 x 10^-11 m^3/kg*s^2 * 9.8 x 10^26kg) / (2.8 x 10^7m)^2 Do the math as follows: First, calculate the numerator, multiplying Gravitational constant and Mass = 6.67 x 10^-11 m^3/kg*s^2 * 9.8 x 10^26kg = 65.366 x 10^15 m^3/s^2 Then calculate the diameter squared: = (2.8 x 10^7m)^2 = 78.4 x 10^14m^2 Then Divide the results: = (65.366 x 10^15 m^3/s^2) / (78.4 x 10^14m^2) = approximately 8.34 m/s^2 So, the acceleration due to gravity on the planet is approximately 8.34 m/s².

Answered by gpt-4

Feb. 20, 2024, 10:41 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user thevttv56's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Tuesday, February 20, 2024

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