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pael_christian

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This image shows the antibacterial contact time of piroctone olamine (left) and farnesol (right) against different types of bacteria. Piroctone olamine was found to have a longer antibacterial contact time than farnesol, which was found to be more effective in killing bacteria.

Antibacterial contact time of piroctone olamine vs farnesol in killing 99.9% of bacteria

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A bar of soap with piroctone olamine and farnesol as its antibacterial ingredients.

Which better antibacterial ingredients in soap? Piroctone olamine vs farnesol

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time?

In this image, a 20A circuit breaker with the trip curve characteristic of "D" can trip instantaneously at 10-20 times of its rated current and can fuse #12AWG wire almost instantly at 184A.

FOR MY EXPERIMENT I have a 20A circuit breaker with the trip-curve characteristics of "D" which it can trip instantaneously at 10-20 times of its rated current and i use #12AWG. In standard computation the fusing current of #12AWG is 235A which can burned the wire almost instantly. In my lab conditions @40°C, the computed time in my experiment is 30 seconds so the fusing current needed for an #12 AWG to melt at exactly 30 seconds time is 184A. Since my circuit breaker is 20A and has trip curve of "D" by looking by its trip curve my computation is when i apply 184A which 9.2 times than the 20A circuit breaker the trip curve show the breaker can trips at around 0.2-1 seconds depends on the environment temperature. Since when i apply 184A of current in #12 AWG it can fused in 30 seconds, then since it's connected to a circuit breaker the circuit breaker will trip at around 0.2-1 seconds based on its trip curve. Does 0.2-1 seconds so slow that it can already melt the wire before it trips 'cause the fusing current is 184A at 30 seconds

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In standard computation, the fusing current of #12AWG is 235A. In my lab conditions @40°C, the computed time in my experiment is 30 seconds. Therefore, the fusing current needed for an #12 AWG to melt at exactly 30 seconds time is 184A. Since my circuit breaker is 40A and has a trip curve of "D," my computation is when I apply 184A, which is 4.6 times than the 40A circuit breaker the trip curve shows the breaker can trips at around 1.5-9 seconds, depending on the environment temperature. Sinc

FOR MY EXPERIMENT I have a 40A circuit breaker with the trip-curve characteristics of "D" which it can trip instantaneously at 10-20 times of its rated current and i use #12AWG. In standard computation the fusing current of #12AWG is 235A which can burned the wire almost instantly. In my lab conditions @40°C, the computed time in my experiment is 30 seconds so the fusing current needed for an #12 AWG to melt at exactly 30 seconds time is 184A. Since my circuit breaker is 40A and has trip curve of "D" by looking by its trip curve my computation is when i apply 184A which 4.6 times than the 40A circuit breaker the trip curve show the breaker can trips at around 1.5-9 seconds depends on the environment temperature. Since when i apply 184A of current in #12 AWG it can fused in 30 seconds, then since it's connected to a circuit breaker the circuit breaker will trip at around 1.5-9 seconds based on its trip curve. Does 1.5-9 seconds so slow that it can already melt the wire before it trips 'cause the fusing current is 184A at 30 seconds

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