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Question: What is the kinetic energy of a 1-kilogram ball is thrown into the air with an initial velocity of 30 m/sec?
To calculate the kinetic energy of the ball, you can use the formula: \[ \text{Kinetic Energy (KE)} = \frac{1}{2}mv^2 \] where: - \( m \) is the mass of the ball (in kilograms), and - \( v \) is the velocity of the ball (in meters per second). Given: - \( m = 1 \) kg, - \( v = 30 \) m/s, Substitute these values into the formula: \[ \text{KE} = \frac{1}{2} \times 1 \times (30)^2 \] \[ \text{KE} = \frac{1}{2} \times 1 \times 900 \] \[ \text{KE} = \frac{900}{2} \] \[ \text{KE} = 450 \text{ joules} \] So, the kinetic energy of the ball is 450 joules.
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