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Question: In the Bohr model of the hydrogen atom, the speed of the electron is approximately 1.96 × 106 m/s. Find the centripetal acceleration on the electron as it revolves in a circular orbit of radius 4.86 × 10−11 m.

Centripetal acceleration of an object moving with a speed (v) in a circular path of radius (r) is given by the formula: a = v² / r Given: v (speed) = 1.96 × 10⁶ m/s r (radius) = 4.86 × 10⁻¹¹ m Using these values in our formula, we can find the centripetal acceleration. a = (1.96 × 10⁶ m/s)² / 4.86 × 10⁻¹¹ m = 3.8416 × 10¹² m²/s² / 4.86 × 10⁻¹¹ m = 7.9023 × 10²² m/s² So the approximate centripetal acceleration of the electron in its orbit is 7.90 × 10²² m/s².

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