![To find Toriano's new average score after withdrawing one test score, we can follow these steps:
1. Calculate the total score from the four exams using the average:
\[
\text{Total score} = \text{Average score} \times \text{Number of exams} = 80 \times 4 = 320
\]
2. Subtract the withdrawn score from the total score:
\[
\text{New total score} = 320 - 53 = 267
\]
3. Calculate the new average score based on the remaining three exams:
\[
\text{New average} = \frac{\text{New](https://theinternetioimages-f2htc2ggcrath6d7.z01.azurefd.net/$web/askai/d7b8f7f6-6b90-4761-9173-8e1f68b08c8c.webp)
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Question: Toriano's average score on last term's four exams was 80. What would Toriano's new average score be if one test's score of 53 was ultimately withdrawn?
To determine Toriano's new average score after removing one exam score, we can follow these steps: 1. Calculate the total score for the four exams given that the average was 80. 2. Subtract the score of the exam that is being withdrawn. 3. Calculate the new average based on the remaining three exams. Let's work through this step by step: 1. **Calculate the total score for the four exams:** Given that the average score for four exams is 80, \[ \text{Total score} = \text{Average score} \times \text{Number of exams} = 80 \times 4 = 320 \] 2. **Subtract the score of the withdrawn exam:** The withdrawn exam score was 53, \[ \text{New total score} = \text{Original total score} - \text{Withdrawn exam score} = 320 - 53 = 267 \] 3. **Calculate the new average based on the remaining three exams:** \[ \text{New average} = \frac{\text{New total score}}{\text{Number of remaining exams}} = \frac{267}{3} = 89 \] So, Toriano's new average score would be 89.
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