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Create an illustration of a large hollow spherical shell in space, labeled with "Outer Radius" and "Inner Radius", highlighting the vacuum inside and arrows indicating the gravitational field extending outward, showing that the gravity is felt outside the shell but not inside it.

The Gravitational Influence of a Hollow Spherical Shell: Understanding Field Effects Inside and Outside

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Question: There exists a hollow spherical shell with an outer radius much much less than its inner radius. It has a significant mass, and is filled with a vacuum. Would this mass create a gravitational field? Where would it be felt, if not everywhere?

Asked by Montenegro

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Let's clarify your question step by step. ### 1. Understanding the Shell You mention: - A **hollow spherical shell** (so all the mass is concentrated in a thin, spherical layer between two radii). - **Outer radius much less than inner radius.** This wording is unusual, because normally for a shell, the outer radius is *greater* than the inner. Perhaps you mean "inner radius much less than outer radius", which is standard. - "Significant mass." - The interior is a vacuum (no extra mass inside). ### 2. Gravitational Field Due to a Spherical Shell This is a classic problem in Newtonian gravity, governed by the shell theorem. #### **Shell Theorem:** - **Outside the Shell:** At any point outside the shell (distance \( r \) from center with \( r > \text{outer radius} \)), the shell's gravitational effect is as if all its mass were concentrated at the center. So, the gravitational field exists and can be felt by an outside object. - **Inside the Shell:** At any point inside the *hollow region* (distance \( r \) from center with \( r < \text{inner radius} \)), the gravitational field is **exactly zero**. The forces from all parts of the shell cancel out. - **Within the Shell Material:** For points in the material of the shell (between inner and outer radius), the field varies linearly, but for a thin shell (inner radius almost the same as outer), you usually don't worry about this region. ### 3. Application to Your Scenario #### **Where the Field Exists:** - **Outside the shell (r > outer radius):** There *is* a gravitational field, just like being at that distance from a point mass at the center. - **Inside the hollow region (r < inner radius):** There is **no gravitational field**. You would feel weightless. #### **"Would this mass create a gravitational field?"** **Yes!** The shell creates a gravitational field. It is felt: - **Everywhere outside the shell** (beyond the shell's outer surface). - **Nowhere inside the hollow region** (the "vacuum" space at the center). --- #### **Summary Table:** | Region | Gravitational field? | |-------------------------------|--------------------------| | < inner radius | **No** (zero field) | | within shell (if thick) | Varies | | > outer radius | **Yes** (like point mass)| --- > **In short:** A massive hollow spherical shell *does* create a gravitational field—it's felt outside the shell as if all the mass were at the center, but *nowhere at all* inside the hollow vacuum region. If you need a more detailed mathematical explanation, just ask!

Answered by gpt-4.1

May 19, 2025, 3:59 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user Montenegro's question. Images were generated with OpenAI's AI model, DALL·E 3. The Internet takes ultimate responsibility for the content of this publication.
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Published: Monday, May 19, 2025

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