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Question: Solve the following system of equations 6x+5y=-10 3x+5y=20
Let's solve the given system step by step: The system is: \[ \begin{cases} 6x + 5y = -10 \\ 3x + 5y = 20 \end{cases} \] ### Step 1: Eliminate one variable Subtract the second equation from the first to eliminate \(y\): \[ (6x + 5y) - (3x + 5y) = -10 - 20 \] \[ 6x - 3x + 5y - 5y = -30 \] \[ 3x = -30 \] ### Step 2: Solve for \(x\) \[ 3x = -30 \implies x = \frac{-30}{3} = -10 \] ### Step 3: Substitute \(x\) into one of the original equations Let's use the second equation: \[ 3x + 5y = 20 \] \[ 3(-10) + 5y = 20 \] \[ -30 + 5y = 20 \] \[ 5y = 20 + 30 = 50 \] \[ y = \frac{50}{5} = 10 \] ### Final Answer: \[ \boxed{x = -10, \quad y = 10} \]
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