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Ask Another Question Browse Other QuestionsQuestion: You and your friend go to a carnival. One of the games is a ring toss. If you can successfully throw a ring on a bottle in three tries, you will receive a giant stuffed teddy bear as a prize. If there are 6 bottles evenly spread out, what is the probability that you will win a teddy bear? Write your answer as a percentage, rounded to the nearest tenth.

To calculate the probability of winning the teddy bear, let's first find the probability of losing the game. The probability of missing a bottle in one try is 5 out of 6, or 5/6, since there are 6 bottles. The probability of missing all three tries is the multiplication of these individual probabilities: (5/6) * (5/6) * (5/6) = 125/216. Now, let's find the probability of winning. The winning probability is the complement of losing probability: 1 - 125/216 = 91/216. Now, convert the winning probability into percentage: (91/216) * 100 ≈ 42.1% So, the probability of winning the teddy bear is approximately 42.1%.

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