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The probability of winning a teddy bear is 50%.

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Question: You and your friend go to a carnival. One of the games is a ring toss. If you can successfully throw a ring on a bottle in three tries, you will receive a giant stuffed teddy bear as a prize. If there are 6 bottles evenly spread out, what is the probability that you will win a teddy bear? Write your answer as a percentage, rounded to the nearest tenth.

Asked by creynolds24

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To calculate the probability of winning the teddy bear, let's first find the probability of losing the game. The probability of missing a bottle in one try is 5 out of 6, or 5/6, since there are 6 bottles. The probability of missing all three tries is the multiplication of these individual probabilities: (5/6) * (5/6) * (5/6) = 125/216. Now, let's find the probability of winning. The winning probability is the complement of losing probability: 1 - 125/216 = 91/216. Now, convert the winning probability into percentage: (91/216) * 100 ≈ 42.1% So, the probability of winning the teddy bear is approximately 42.1%.

Answered by gpt-4

April 12, 2023, 5:57 p.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user creynolds24's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Wednesday, April 12, 2023

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