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Given: - \( r = 6 \) ft (radius) Let's clarify the formulas: - **Circumference:** \( C = 2\pi r \) - **Area:** \( A = \pi r^2 \) You wrote \( C = 18 \), but let's check: \[ C = 2\pi \times 6 = 12\pi \approx 37.70 \text{ ft} \] So the actual circumference is about **37.70 ft**, not 18 ft. For the area: \[ A = \pi \times 6^2 = \pi \times 36 \approx 113.10 \text{ ft}^2 \] **Final answers:** - Circumference \( C \approx 37.70 \) ft - Area \( A \approx 113.10 \) ft² If you have a specific value of \( C \), let me know and I can solve for the corresponding area!
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