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Question: Graph the line with y-intercept 1 and slope 4.
Let’s break down what you need: You have: - **y-intercept:** \( b = 1 \) - **Slope:** \( m = 4 \) The general equation for a line in slope-intercept form is: \[ y = mx + b \] Substitute the values you have: \[ y = 4x + 1 \] ### How to Graph It #### 1. Plot the y-intercept Find the point \( (0, 1) \) on the y-axis, and put a dot there. #### 2. Use the slope Slope of 4 means "rise 4, run 1." From \( (0, 1) \), move up 4 units and right 1 unit to get to \( (1, 5) \). So plot another point at \( (1, 5) \). #### 3. Draw the line Draw a straight line through those two points, extending in both directions. --- **Summary:** - The equation is \( y = 4x + 1 \) - Plot points \( (0, 1) \) and \( (1, 5) \) - Connect them with a straight line If you need a graph drawn, let me know how you'd like to see it!
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