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Question: Find the perimeter and area of the rectangle with vertices (-3, 3), (4, 3),(4, -7), and (-3, -7)
Given **vertices** of the rectangle: A \((-3, 3)\), B \((4, 3)\), C \((4, -7)\), D \((-3, -7)\) Let's find the **side lengths** first. ### 1. Find the Side Lengths Let’s look at AB and BC: - **AB**: from \((-3, 3)\) to \((4, 3)\) This is a horizontal distance: \[ \text{Length of AB} = |4 - (-3)| = |4 + 3| = 7 \] - **BC**: from \((4, 3)\) to \((4, -7)\) This is a vertical distance: \[ \text{Length of BC} = |3 - (-7)| = |3 + 7| = 10 \] So, the rectangle's **lengths** are **7** and **10**. --- ### 2. **Perimeter** A perimeter of rectangle = \(2 \times (\text{length} + \text{width})\) \[ \text{Perimeter} = 2 \times (7 + 10) = 2 \times 17 = 34 \] --- ### 3. **Area** Area of rectangle = \(\text{length} \times \text{width}\) \[ \text{Area} = 7 \times 10 = 70 \] --- ## **Final Answers** - **Perimeter:** \(\boxed{34}\) units - **Area:** \(\boxed{70}\) square units
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