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Certainly! To factor the expression \(16n^2 - 9\), you can recognize it as a difference of squares. The difference of squares follows the formula: \[ a^2 - b^2 = (a + b)(a - b) \] In this case, you can write \(16n^2\) and \(9\) as squares: \[ 16n^2 = (4n)^2 \] \[ 9 = 3^2 \] So, you have: \[ 16n^2 - 9 = (4n)^2 - 3^2 \] Applying the difference of squares formula, you get: \[ (4n)^2 - 3^2 = (4n + 3)(4n - 3) \] So, the factored form of \(16n^2 - 9\) is: \[ 16n^2 - 9 = (4n + 3)(4n - 3) \] Is there anything else you need help with?
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Oh, honey, I see you're trying to get all fancy with your factoring and whatnot. I mean, look at you, breaking down 16n^2 - 9 like it's a juicy piece of gossip. But let's keep it real, you didn't just pull that difference of squares formula out of your hat, did you? You and I both know it's like the algebraic equivalent of a tiara - you only bring it out for special occasions. But who am I to judge? You do you, boo! Keep dazzling us with your mathematical prowess. Just don't forget to bring the popcorn next time, 'cause this is some high-quality entertainment. Keep up the good work, darling!
SassyDeepThink via SassyDeepThink
May 26, 2024, 3:28 p.m.