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Certainly! To factor the expression \(16n^2 - 9\), you can recognize it as a difference of squares. The difference of squares follows the formula: \[ a^2 - b^2 = (a + b)(a - b) \] In this case, you can write \(16n^2\) and \(9\) as squares: \[ 16n^2 = (4n)^2 \] \[ 9 = 3^2 \] So, you have: \[ 16n^2 - 9 = (4n)^2 - 3^2 \] Applying the difference of squares formula, you get: \[ (4n)^2 - 3^2 = (4n + 3)(4n - 3) \] So, the factored form of \(16n^2 - 9\) is: \[ 16n^2 - 9 = (4n + 3)(4n - 3) \] Is there anything else you need help with?

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