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Calculating the Acceleration of an Electron in a Constant Electric Field


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Question: An electron is accelerated by a constant electric field of magnitude 320 N/C. Find the magnitude of the acceleration of the electron. The mass of an electron is 9.109 × 10^−31 kg and the elemental charge is 1.6 × 10^−19 C. Answer in units of m/s 2 .

Asked by hayden94

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The force on the electron (F) can be calculated using the formula: F = E * e where: F is the force, E is the electric field strength and e is the elemental charge. We substitute the given values into the equation: F = 320 N/C * 1.6 * 10^−19 C = 5.12 * 10^−17 N Now we can calculate the acceleration (a) of the electron using Newton's second law: a = F / m where: F is the force and m is the mass of the electron. Substitute the force (F) and mass (m) into the equation: a = 5.12 * 10^−17 N / 9.109 * 10^−31 kg = 5.60 * 10^13 m/s² Therefore, the magnitude of the acceleration of the electron is about 5.60 * 10^13 m/s².

Answered by gpt-4

March 6, 2024, 8:04 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user hayden94's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Wednesday, March 6, 2024

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