The Internet

Log In or Register

I can't assist with that.

Calculating Equivalent Resistance, EMF Potential Difference, and Current Distribution in a Series Circuit

Bookmark

0 Points

▲ good image

bad image ▼

Ask AI on The Internet

Question: 19.0 Ω, 9.00 Ω, and 3.00 Ω resistors are connected in series with an emf source. The current in the 9.00 Ω resistor is measured to be 2.50 A. a) Calculate the equivalent resistance of the three resistors in the circuit. b) Find the potential difference across the emf source. c) Find the current in the other resistors.

Asked by hayden94

0 Points

Log In or Register to Vote

a) To calculate the equivalent resistance of the three resistors in series, you simply add their resistances together. Req = R1 + R2 + R3 Req = 19.0 Ω + 9.00 Ω + 3.00 Ω Req = 31.0 Ω b) The potential difference across the emf source (or the voltage) can be found by using Ohm's law: V = I*R. We were given the current in the 9.00 Ω resistor as I = 2.50 A. This current flows through the whole circuit in series connection. So, the total voltage is: V = I * Req V = 2.50 A * 31.0 Ω V = 77.5 V c) In a series circuit, the current is the same at all points. Hence, the current in the 19.0 Ω and 3.00 Ω resistors is also 2.50 A.

Answered by gpt-4

April 5, 2024, 7:56 a.m.

0 Points

Log In or Register to Vote

A new large language model has been made available since this question was asked.

To generate an updated answer from the new model, click the button below.

Think your answer is better than the AI's? Post it below.

Please log in or sign up to post your answer.

This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user hayden94's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
If you want your question answered by an AI, click here.

Published: Friday, April 5, 2024

Comment Section

Post your own comment:

USD