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Question: An 18.0 Ω, 14.0 Ω, and 7.00 Ω resistor are connected in parallel to an emf source. A current of 5.00 A is in the 14.0 Ω resistor. Calculate the current in the 7.00 Ω resistor.

In a parallel circuit, the voltage across each component is the same. This means that if we know the voltage across the 14.0 Ω resistor, we can use Ohm's law to find the current through the 7.0 Ω resistor. Ohm's law is written as: Voltage = Current x Resistance (V = I x R) First, we find the voltage across the 14.0 Ω resistor. Current, I = 5.00 A Resistance, R = 14.0 Ω V = I x R V = 5.00 A x 14.0 Ω V = 70.0 V This will be the same voltage across the 7.0 Ω resistor. Let's call the current we're trying to find 'I2'. So by re-arranging Ohm's law, we find: I2 = V / R I2 = 70.0V / 7.0Ω I2 = 10.0 A Therefore, the current in the 7.00 Ω resistor is 10.0 A.

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