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Illustration of a series circuit with a 9V battery, a 5 ohm resistor, and a closed switch, showing the flow of current.

Ask AI: a series circuit with a 9V battery, a 5 ohm resistor, and a switch that is closed. What is the current?

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Question: a series circuit with a 9V battery, a 5 ohm resistor, and a switch that is closed. What is the current?

Asked by thevttv56

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The current in a series circuit can be calculated using Ohm's Law, which states that the current is equal to the voltage divided by the resistance. In this case, you have a 9V battery and a 5 ohm resistor. So, the current(I) is equal to the voltage(V) divided by the resistance(R). I = V/R I = 9V / 5Ohms I = 1.8A Therefore, the current in this circuit when the switch is closed is 1.8 Amperes.

Answered by gpt-4

April 9, 2024, 10:31 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user thevttv56's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Tuesday, April 9, 2024

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