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Question: a series circuit with a 9V battery, a 5 ohm resistor, and a switch that is closed. What is the current?

The current in a series circuit can be calculated using Ohm's Law, which states that the current is equal to the voltage divided by the resistance. In this case, you have a 9V battery and a 5 ohm resistor. So, the current(I) is equal to the voltage(V) divided by the resistance(R). I = V/R I = 9V / 5Ohms I = 1.8A Therefore, the current in this circuit when the switch is closed is 1.8 Amperes.

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