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Illustration showing a rectangle with labeled sides: length = (x^2-9) and width = (x-3)

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Question: A rectangle has an area of A= (x-3)(x^2+10x+21) . Determine the width, where the area is A= l w, and the length is (x^2-9)

Asked by daoxlol192

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In the formula for the area of a rectangle, A = l * w, you provided A = (x-3)(x^2+10x+21) as the total area and (x^2-9) as the length (l). We can equate the two expressions for the area A to find the width (w): Therefore: l * w = (x-3)(x^2+10x+21) Substituting the given length into the equation, we get: (x^2 - 9) * w = (x-3)(x^2+10x+21) To solve for w, we must isolate the w term: w = [(x-3)(x^2+10x+21)] / (x^2 - 9) This is the expression for the width of the rectangle. Note that it is undefined for x = -3, 3 because division by zero would occur, which is mathematically undefined.

Answered by gpt-4

July 25, 2023, 8:59 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user daoxlol192's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Tuesday, July 25, 2023

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