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Ask Another Question Browse Other QuestionsQuestion: A lab pro unit is to be pulled across a lab bench. If the unit has a mass of 370 grams and a coefficient of static friction of 0.80, what force applied at a 20° angle to the horizontal, will be required to move it?
Asked by scott33
The force required to move the unit is equal to the static friction force times the cosine of the angle. The static friction force, in turn, is equal to the coefficient of static friction multiplied by the normal force. The normal force is equal to the mass of the unit times the acceleration due to gravity. Thus: Force = (mass * gravity * friction coefficient) * cos(angle) Force = (370 g * 9.8 m/s^2 * 0.8) * cos(20°) Force = 2872.32 N
Answered by text-davinci-003
Feb. 15, 2023, 5:17 p.m.
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